Students can Download Basic Maths Question Bank Chapter 17 Limit and continuity of a function Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

## Karnataka 2nd PUC Basic Maths Question Bank Chapter 17 Limit and Continuity of a Function

### 2nd PUC Basic Maths Limit and Continuity of a Function One Mark Questions and Answers

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### 2nd PUC Basic Maths Limit and Continuity of a Function Two Marks Questions and Answers

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### 2nd PUC Basic Maths Rationalization Method Three or Four Marks Questions and Answers

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### 2nd PUC Basic Maths Limits Tending to ∞ Three or Four Marks Questions and Answers

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### 2nd PUC Basic Maths Limits and Continuity of a Function Five or Six Marks Questions and Answers

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(i.e,n is +ve, -ve and a fraction.)

Problems from standand limits with solution. (One or Two M. Q.)

Evaluate the soloving:

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Put y = x – 1

y + 1 =x

As x → 1

y → 40

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Continuity of a function:

A function y =fx) is said to be continuous at x = a if f(a) exists and ¡s equal to f(a)

i.e. \(\lim _{x \rightarrow a}\) f(x) = f(a)

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A function y = f(x) is said to be continuous at x = a. If \(\lim _{x \rightarrow a^{+}}\) f(x) = \(\lim _{x \rightarrow a^{-}}\) = f(x) = f(a) i.e., R.H.L. = L.H.L = f(a).

### 2nd PUC Basic Maths Continuity of a Function Three or Four Marks Questions and Answers

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S.T. the function f(x) = |x| is continuous at x = 0.

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Define f(0) So that f(x) = \(\frac{x}{1-\sqrt{1-x}}\) becomes continous at x = 0 and f(0) = 2.

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f(0) = \(\frac{0}{1-\sqrt{1-0}}=\frac{0}{1-1}=\frac{0}{0}\) form, which is inditerminate hence rationalize the D.N.R.

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