KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1

Students can Download Class 10 Maths Chapter 13 Statistics Ex 13.1 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 10 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

Karnataka State Syllabus Class 10 Maths Chapter 13 Statistics Ex 13.1

Question 1.
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 1
Which method did you use for finding mean and why?
Answer:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 2
Mean number of plants per house is 8.1. Direct method because Xi and fi are small.

KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1

Question 2.
Consider the following distribution of daily wages of 50 workers of a factory.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 3
Find the mean daily wages of the workers of the factory by using an appropriate method.
Answer:
By step deviation method.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 4
assumed mean = a = 550,
Common factor = h = 20 [from class mark]
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 5
Mean daily wages of the workers in the factory is ₹ 145.20.

Question 3.
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is ₹ 18. Find the missing frequency f.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 6
Answer:
Mean = \(\overline{\mathbf{x}}\) = 18
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 7
18(f + 44) = 20f + 752
18f + 792 = 20f + 752
792 – 752 = 20f – 18f
2f = 40
f = \(\frac{40}{2}\)
Hence missing frequency is 20

KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1

Question 4.
Thirty women were examined in a hospital by a doctor and the number of heart beats per minute were recorded and summarised as follows. Find the mean heart beats per minute for these women, choosing a suitable method.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 8
Answer:
Step deviation method.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 9
Assumed mean = a = 75.5
Common factor = h = 1 [From class mark]
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 10
Mean of heart beats per minute is 75.9

Question 5.
In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number of mangoes. The following was the distribution of mangoes according to the number of boxes.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 11
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Answer:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 12
Assumed mean = a = 57
Common factor = h = 3 [common factor from class mark ]
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 13
Mean number of mango’s kept in box is 57.19.

KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1

Question 6.
The table below shows the daily expenditure on food of 25 households in a locality.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 14
Find the mean daily expenditure on food by a suitable method.
Answer:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 15
assumed mean = a = 225
Common factor = h = 25 [from class mark]
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 16
Hence, the mean daily expenditure of food is ₹ 211

Question 7.
To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 17
Find the mean concentration of SO2 in the air.
Answer:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 18
assumed mean = a = 0.10
Common factor = h = 0.02 [class mark]
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 19
∴ The mean concentration of SO2 in the air is 0.099 ppm.

KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1

Question 8.
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 20
Answer:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 21
Mean number of days student was absent is 12.47.

Question 9.
The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 22
Answer:
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 23
Assume mean = a = 70
Class size = h = 10.
KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1 24
= 70 – 0.57 = 69.43
∴ Mean literacy rate is 69.43%

KSEEB Solutions for Class 10 Maths Chapter 13 Statistics Ex 13.1