Students can download Chapter 3 Playing with Numbers Ex 3.1 KSEEB Solutions for Class 6 Maths helps you to revise the complete syllabus.

## Karnataka State Syllabus Class 6 Maths Chapter 3 Playing with Numbers Ex 3.1

Question 1.

Write all the factors of the following numbers:

a) 24

b) 15

c) 21

d) 27

e) 12

f) 20

g) 18

h) 23

i) 36

Solution:

a) 24 :-

24 = 1 × 24, 24 = 2 × 12; 24 = 3 × 8

= 24 = 4 × 6 ; 24 = 6 x 4 ;

∴ Factors of 24 are 1, 2, 3, 4, 6, 8, 12 & 24

b) 15:-

15 = 1 × 15; 15 = 3 × 5; 15 = 5 × 3

∴ Factors of 15 are 1, 3, 5 and 15

c) 21:-

21 = 1 × 21 ; 21 = 3 × 7; 21 = 7 × 3

∴ Factors of 21 are 1, 3, 7 and 21

d) 27:-

27 = 1 × 27; 27 = 3 × 9; 21 =9 × 3

∴ Factors of 27 are 1, 3, 9 and 27

e) 12:-

12 = 1 × 12; 12 = 2 × 6; 12 = 4 × 3

∴ Factors of 12 are 1, 2, 3, 4, 6 and 12

f) 20:-

20 = 1 × 20 ; 20 = 2 × 10; 20 = 4 × 5; 20 = 5 × 4 ; 20 = 10 × 2

∴ Factors of20 are 1, 2, 4, 5, 10 and 20

g) 18:-

18 = 1 ×18; 18 = 2 × 9; 18 = 3 × 6; 18 = 6 × 3

∴ Factors of 18 are 1, 2, 3, 6, 9 and 18

h) 23:-

23 = 1 × 23 ; 23 = 23 × 1

∴ Factors of 23 are 1 and 23

i) 36:-

36 = 1 × 36; 36 = 2 × 18; 36 = 3 × 12; 36 = 4 × 9; 36 = 6 × 6

∴ Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18 and 36.

Question 2.

Write first five multiples of:

a) 5

b) 8

c) 9

Solution:

a) 5 = 5 × 1= 5; 5 × 2 = 10; 5 × 3 = 15; 5 × 4 = 20; 5 × 5 = 25. 5, 10, 15, 2, 25

b) 8 = 8 × 1 = 8; 8 × 2 = 16; 8 × 3 = 24; 8 × 4 = 32; 8 × 5 =40. 8,16,24,32,40

c) 9 = 9 × 1 = 9; 9 × 2 = 18; 9 × 3 = 27; 9 × 4 = 36; 9 × 5 = 45. 9,18,27,36,45

Question 3.

Match the items in column 1 with the items in column 2.

Solution:

1 – b,

2 – d,

3 – a,

4 – f,

5 – e.

Question 4.

Find all the multiples of 9 upto 100.

Solution:

Therefore the multiples of 9 up to 100 are

9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99.