Students can download Chapter 7 Fractions Ex 7.6 KSEEB Solutions for Class 6 Maths helps you to revise the complete syllabus.

## Karnataka State Syllabus Class 6 Maths Chapter 7 Fractions Ex 7.6

Question 1.

Solve

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Taking 6 as L.C.M.

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(Taking 12 as L.C.M)

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(Taking 6 as L.C.M)

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Question 2.

Santa bought \(\frac{2}{5}\) metre of ribbon and Lalita \(\frac{3}{4}\) metre of ribbon. What is the total length of the ribbon they bought?

Solution:

Length of ribbon bought by Sarita = \(\frac{2}{5}\) m

Length of ribbon bought by Lalita = \(\frac{3}{4}\) m

Total length of ribbon bought by them = \(\frac{2}{5}+\frac{3}{4}\)

Question 3.

Naina was given 1\(\frac{2}{5}\) piece of cake and Najma was given 1\(\frac{1}{3}\) piece of cake. Find the total amount of cake was given to both of them.

Solution:

Fraction Naina got = \(1 \frac{1}{2}=\frac{3}{2}\)

Fraction Najma got = \(1 \frac{1}{3}=\frac{4}{3}\)

Total amount of cake to them

Question 4.

Fill in the blanks

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Question 5.

Complete the addition – subtraction box.

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Question 6.

A piece of wire \(\frac{7}{8}\) metre long broke into two pieces. One-piece was \(\frac{1}{4}\) metre long. How long is the other piece?

Solution:

Length of one piece = \(\frac{1}{4}\) m

The length of the other piece of wire will be the difference of the length of the original wire

Hence, Length of the other piece of wire = \(\frac{7}{8}-\frac{1}{4}=\frac{7-(1 \times 2)}{8}-\frac{7-2}{8}=\frac{5}{8} \mathrm{m}\)

Question 7.

Nandini’s house is \(\frac{9}{10}\) km from her school. She walked some distance and then took a bus for \(\frac{1}{2}\) km to reach the school. How far did she walk?

Solution:

Distance walked by Nandhini = Total distance – Distance for Which she took the bus

Question 8.

Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is \(\frac{5}{6}\) th full and Samuel’s shelf is \(\frac{2}{5}\) th full. Whose bookshelf is more full? By what fraction?

Solution:

Converting these into like fractions

Clearly, Asha’s bookshelf is more full

Question 9.

Jaidev takes 2 \(\frac{1}{5}\) minutes to walk across the school ground. Rahul takes \(\frac{7}{4}\) to do the same. Who takes less time and by What fraction?

Solution:

Time taken by Jaidev = 2\(\frac{1}{5}\) minutes = \(\frac{11}{5}\) min

Time taken by Rahul = \(\frac{7}{4}\) min

Converting these into like fractions.

As 44 > 35

Hence, Rahul takes lesser time