KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Students can Download Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

Karnataka State Syllabus Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 1.
Tell what is the profit or loss in the following transactions. also find profit percent or loss percent in each case.
a) Gardening shears bought for ₹ 250 and sold for ₹ 325.
Solution:
C. P = Rs 250
S. P = Rs. 325
S.P > C.P
∴ It is profit.
Total profit = S.P – C.P
= 325 – 250 = Rs 75
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 1

b) A refrigerator bought for ₹ 12,000 and sold at ₹ 13,500.
Solution:
C. P = Rs. 12,000
S.P = Rs. 13,500
S.P > C.P
It is profit
Total profit = S. P – C. P
= 13,500 – 12,000
= Rs.1,500/-
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 2

c) A cupboard bought for ₹ 2,500 and sold at ₹ 3,000.
Solution:
C.P = Rs. 2,500
S. P = Rs. 3,000
S.P > C.P
It is profit
Total profit = S. P – C. P
= 3000 – 2500
= Rs. 500
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 3

d) A skirt bought for 250 and sold at ₹ 150.
C.P = Rs. 250/-
S.P = Rs. 150/-
S.P < C.P
∴ It is loss
Total loss = C.P – S.P
= 250 – 150 = Rs. 100
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 4

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Percentage Difference Calculator is very simple app to calculate percentage difference between 2 values.

Question 2.
Convert each part of the ratio to percentage :
a) 3 : 1
Solution:
Total parts = 3 + 1 = 4
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 5

b) 2 : 3 : 5
Solution:
Total parts = 2 + 3 + 5 = 10
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 6
∴ Percentage of part is 30%
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 7

c) 1 : 4
Total parts = 1 + 4 = 5
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 8
∴ Percentage of part 4 is 80%

d) 1 : 2 : 5
Total parts. = 1 + 2 + 5 = 8
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 9

Question 3.
The population of a city decreased from 25,000 to 24,500. Find the percentage decrease.
Solution:
Decreased population = 25,000 – 24,500 = 500
Percentage of decrease =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 10

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Use this percent decrease calculator to easily calculate the result from a percentage decrease by any amount.

Question 4.
Arun bought a car for 3, 50, 000. The next year, the price went upto ₹ 3,70,000. What was the percentage of the price increase?
Solution:
Price of a car = Rs. 3,50,000
Increased price of a car = Rs. 3,70,000
Total increase = Rs. 20,000
Percentage of price increase =
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 11

Question 5.
I buy a T. V. for ₹ 10,000 and sell it at a profit of 20%. How much money do I get for it?
Solution:
C.P of a T.V = Rs. 10,000
Profit = 20%
20% of Rs. 10,000
Total profit = \(\frac{2}{100}\) × 10,000 = ₹ 2,000
∴ Amount I get = C. P + profit
= 10,000 + 2,000
= Rs. 12,000

Question 6.
Juhi sells a washing machine for ₹ 13,500. She loses 20% in the bargain. What was the price at which she bought it ?
Solution:
We have,
The selling price of the washing machine for ₹ 13,500.
Loss of percent = 20%
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 12
∴ She bought that washing machine for Rs. 16,875.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

To convert CGPA into percentage, multiply the CGPA with 9.5 to get the overall indicative percentage.

Question 7.
i) Chalk contains calcium, carbon, and oxygen in the ratio 10 : 3 : 12. Find the percentage of carbon in chalk.
Solution:
Total parts = 10 + 3 + 12 = 25
percentage of carbon
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 13

ii) If in a stick of chalk. carbon is 3g, what is the chalk stick?
Solution:
Let the weight of chalk stick be ‘M’
Then 12% of M = 3
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 14
∴ The weight of the chalk stick is 25 grams.

Question 8.
Amina buys a book for ₹ 275 and sells it at a loss of 15%. How much does she sell it for?
Solution:
C. P of a book = Rs. 275
loss = 15% of C. P
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 15
S.P = C.P – Loss
= 275 – 41.25
= Rs. 233.751
∴ She sells it for Rs. 233.75.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 9.
Find the amount to be paid at the end of 3 years in each case:
a) Principal = ₹ 1,200 at 12 % p.a
P = Rs. 1200/-
R = 12%
T = 3 years
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 16
A = P + I = 1200 + 432 = Rs. 1,632
∴ The amount paid at the end of 3 years is Rs. 1,632

b) Principal = ₹ 7,500 at 5% p.a
P = Rs. 7,500
R = 5%
T = 3 years
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 17
A = P + I
= 7500 + 1125
= Rs. 8,625
∴ The amount to be paid at the end of 3 years is Rs. 8,625.

Question 10.
What rate gives ₹ 280 as interest on a sum of ₹ 56,000 in 2 years?
Solution:
P = Rs. 56,000/-
R =?
T = 2 years
I = Rs. 280
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 18
∴ The rate of interest is 0.25% per annum.

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3

Question 11.
If Meena gives an interest of 45 for one year at 9% rate p.a. What is the sum she has borrowed?
Solution:
P =?
R = 9%
T = 1 years
I = Rs. 45
KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 19
∴ She has borrowed the sum of Rs. 500

KSEEB Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3