KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.4

Students can Download Class 8 Maths Chapter 10 Exponents Ex 10.4 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

Karnataka State Syllabus Class 8 Maths Chapter 10 Exponents Ex 10.4

Question 1.
Simplify
(i) $\frac{\left(2^{5}\right)^{6} \times\left(3^{3}\right)^{2}}{\left(2^{6}\right)^{5} \times\left(3^{2}\right)^{3}}$

Answer:

(ii) $\frac{\left(5^{-3}\right)^{2} \times 3^{4}}{\left(3^{-2}\right)^{-3} \times\left(5^{3}\right)^{-2}}$
Answer:

Question 2.
Can you find two integers m and n such that 2m+“ = 2m”?
Answer:
m + n = mn
2 + 2 = 2 x 2
4 = 4
∴ m = 2 & n = 2

Question 3.
If (2^m)⁴ = 4⁶ find the value of m.
Answer:
(2^m)⁴ = 4⁶ (a^m)ⁿ = a^mn
(2^m)⁴ = 4⁶
(2^m)⁴ = (2²)⁶
2^{m × 4} = 2^{2 × 6}
2^4m = 2¹²
∴ 4m = 12
m = $\frac { 12 }{ 4 }$
m = 3