KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7

Students can Download Class 8 Maths Chapter 10 Exponents Ex 10.7 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

Karnataka State Syllabus Class 8 Maths Chapter 10 Exponents Ex 10.7

Question 1.
Use the laws of exponents and simplify
Answer:
(i) \(\frac{(12)^{6}}{162} ?\)
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 1

(ii) KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 9
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 2

(iii) \(\frac{2^{3^{2}}}{\left(2^{3}\right)^{2}}\)
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 4

Question 2.
What is the value of \(\frac{\left(10^{3}\right)^{2} \times 10^{-4}}{10^{2}}\)
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 5

Question 3
Simplify:
\(\left[\frac{b^{-3} \cdot b^{7} \cdot\left(b^{-1}\right)^{2}}{(-b)^{2}\left(b^{2}\right)^{3}}\right]^{-2}\)
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 6

KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7

Question 4.
Find the value of each of the following expressions.
(a). (32)2 – (-2)3)2 – (-(5)2)2
= 34 – (- 2 x – 2 x – 2)2 – (-52 )2
= 34 – (-23)2 – 54
= 81 – 26 – 625
= 81- 64 – 625
= 81 – 689
= -608

(b). ((0.6)2)0– ((4.5)0)-2
= (0.6)2 x 0 – (4.5)0 x -2
= (0.6)0 – (4.5)0
= 1-1
= 0

(c).
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7 8

KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7