KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6

Students can Download Class 8 Maths Chapter 10 Exponents Ex 10.6 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

Karnataka State Syllabus Class 8 Maths Chapter 10 Exponents Ex 10.6

Question 1.
Simplify
(i). \left(\frac{2}{3}\right)^{8} \times\left(\frac{6}{4}\right)^{3}
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6 1

(ii). (1.8)6 × (4.2)-3
Answer:

KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6 3

(iii). \frac{(0.0006)^{3}}{(0.015)^{-4}}
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6 4

Question 2.
Can it happen that for some integer m ≠ 0 \left(\frac{4}{25}\right)^{m} = \left(\frac{2}{5}\right)^{\mathrm{m}^{2}} ?
Answer:
KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex. 10.6 5
∴ m2 = 2m
m.m = 2m
m = 2
It can happen if m = 2

KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6

Question 3.
Find all positive integers m, n such that (3m)n = 3m × 3n
Answer:
(3m)n = 3m × 3n
3mn = 3m+n
mn = m+n
2.2 = 2 + 2
∴ m = 2, n = 2
(m, n) = (2, 2)

KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6