KSEEB Solutions for Class 8 Maths Chapter 13 Statistics Ex 13.3

Students can Download Class 8 Maths Chapter 13 Statistics Ex 13.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

Karnataka State Syllabus Class 8 Maths Chapter 13 Statistics Ex 13.3

Question 1.
Runs scored by 10 batsman in a one day cricket match are given. Find the average run scored. 23, 54, 08, 94, 60, 18, 29, 44, 05, 86
Answer:
Σ x = 23 + 54 + 08 + 94 + 60 + 18 + 29 + 44 + 05 + 86 = 421
N = 10
Average = Mean = $\overline{X}=\frac{\Sigma x}{N}=\frac{421}{10}=42.1$

Question 2.
Find the mean weight form the following table:

Answer:

Mean = $\frac{\Sigma f_{X}}{N}=\frac{473}{15}=31.53$

Question 3.
Calculate the mean for the following frequency distribution.

Answer:

Mean = $\frac{\Sigma f_{x}}{N}=\frac{1710}{40}=42.75$ Answer:

Question 4.
Calculate the mean for the following frequency distribution.
Answer:

Mean = $\overline{X}=\frac{\Sigma f_{X}}{N}=\frac{1145}{40}=28.625$

Question 5.
Find the median of the data 15,22, 9,20, 6,18,11,25,14.
Answer:
6, 9, 11, 14,(15), 18, 20, 22,25 (Ascending order)
N = 9,
$\frac{N+1}{2}+\frac{9+1}{2}=\frac{10}{2}=5^{\text { th }}$
Median = 15.

Question 6.
Find the median of the data 22, 28, 34, 49, 44, 57, 18, 10, 33, 41, 66, 59
Answer:
10, 18, 22, 28, 33, 34, 41, 44, 49, 57, 59, 66 (Ascending order)
N = 10
∴ Median = $\frac{34+41}{2}=\frac{75}{2}=37.5$

Question 7.
Find the median for the following frequency distribution table.

Answer: