Students can Download Class 8 Maths Chapter 13 Statistics Ex 13.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and to clear all their doubts, score well in final exams.

## Karnataka State Syllabus Class 8 Maths Chapter 13 Statistics Ex 13.3

Question 1.

Runs scored by 10 batsman in a one day cricket match are given. Find the average run scored. 23, 54, 08, 94, 60, 18, 29, 44, 05, 86

Answer:

Σ x = 23 + 54 + 08 + 94 + 60 + 18 + 29 + 44 + 05 + 86 = 421

N = 10

Average = Mean = \(\overline{X}=\frac{\Sigma x}{N}=\frac{421}{10}=42.1\)

Question 2.

Find the mean weight form the following table:

Answer:

Mean =

Question 3.

Calculate the mean for the following frequency distribution.

Answer:

Mean = Answer:

Question 4.

Calculate the mean for the following frequency distribution.

Answer:

Mean =

Question 5.

Find the median of the data 15,22, 9,20, 6,18,11,25,14.

Answer:

6, 9, 11, 14,(15), 18, 20, 22,25 (Ascending order)

N = 9,

\(\frac{N+1}{2}+\frac{9+1}{2}=\frac{10}{2}=5^{\text { th }}\)

Median = 15.

Question 6.

Find the median of the data 22, 28, 34, 49, 44, 57, 18, 10, 33, 41, 66, 59

Answer:

10, 18, 22, 28, 33, 34, 41, 44, 49, 57, 59, 66 (Ascending order)

N = 10

∴ Median = \(\frac{34+41}{2}=\frac{75}{2}=37.5\)

Question 7.

Find the median for the following frequency distribution table.

Answer:

N = 50

∴ Median class is 130 – 139

LRL = 129.5

Fc = 14

Fm = 15

i = 10

Question 8.

Find the median for the following frequency distribution table.

Answer:

N = 40

∴ Median class is 15 – 20

LRL = 15

Fc = 17

Fm = 9

i = 5

Question 9.

Find the mode for the following data.

(i) 4,3,1,5,3, 7, 9,6

Answer:

Mode = 3

(ii) 22,36,18,22,20,34,22, 42, 46,42

Answer:

Mode = 22

Question 10.

Find the mode for the following data

Answer:

Mode = 20 (It has the highest frequency)